Write the complex number z=frac3+4i1−2iz = \\frac{3 + 4i}{1 - 2i}z=frac3+4i1−2i in standard form a+bia + bia+bi.
−frac15+frac25i-\\frac{1}{5} + \\frac{2}{5}i−frac15+frac25i
−1+2i-1 + 2i−1+2i
−1+frac105i-1 + \\frac{10}{5}i−1+frac105i