Which value of xxx satisfies 4x−2x−12=04^x - 2^x - 12 = 04x−2x−12=0?
x=2x = 2x=2
x=log2(3)x = \log_2(3)x=log2(3)
x=3x = 3x=3
x=3x = \sqrt{3}x=3