Which value must be excluded from the solution of 5x−1=x+2x2−1\dfrac{5}{x-1} = \dfrac{x+2}{x^2-1}x−15=x2−1x+2?
x=1x = 1x=1 and x=−1x = -1x=−1
x=1x = 1x=1 only
x=−1x = -1x=−1 only
No exclusions needed