Which transformation is appropriate to linearize the power law model Y=αXβY = \alpha X^{\beta}Y=αXβ?
ln(Y)=ln(α)+βln(X)\ln(Y) = \ln(\alpha) + \beta \ln(X)ln(Y)=ln(α)+βln(X)
ln(Y)=βln(X)+ln(α)\ln(Y) = \beta \ln(X) + \ln(\alpha)ln(Y)=βln(X)+ln(α)
Y=α+βXY = \alpha + \beta XY=α+βX
log10(Y)=log10(α)+βlog10(X)\log_{10}(Y) = \log_{10}(\alpha) + \beta \log_{10}(X)log10(Y)=log10(α)+βlog10(X)