Which substitution verifies that x=2x = 2x=2 satisfies x3−2x2+x−2=0x^3 - 2x^2 + x - 2 = 0x3−2x2+x−2=0?
8−8+2−2=08 - 8 + 2 - 2 = 08−8+2−2=0 ✓
8+8+2−2=16≠08 + 8 + 2 - 2 = 16 \neq 08+8+2−2=16=0
8−8−2−2=−4≠08 - 8 - 2 - 2 = -4 \neq 08−8−2−2=−4=0
4−8+2−2=−4≠04 - 8 + 2 - 2 = -4 \neq 04−8+2−2=−4=0