Which statement about matrix rank is false?
The rank of an m×nm \times nm×n matrix is at most min(m,n)\min(m, n)min(m,n)
If AAA is n×nn \times nn×n and rank(A)=n\text{rank}(A) = nrank(A)=n, then AAA is invertible
rank(A)=rank(AT)\text{rank}(A) = \text{rank}(A^T)rank(A)=rank(AT) for any matrix AAA
An m×nm \times nm×n matrix with rank 0 has no zero rows