Which series converges by the Alternating Series Test?
∑n=1∞(−1)nn+1n\sum_{n=1}^{\infty} (-1)^n \frac{n+1}{n}∑n=1∞(−1)nnn+1
∑n=1∞(−1)n1ln(n+1)\sum_{n=1}^{\infty} (-1)^n \frac{1}{\ln(n+1)}∑n=1∞(−1)nln(n+1)1
∑n=1∞(−1)nn2n2+1\sum_{n=1}^{\infty} (-1)^n \frac{n^2}{n^2+1}∑n=1∞(−1)nn2+1n2
∑n=1∞(−1)ncos(n)\sum_{n=1}^{\infty} (-1)^n \cos(n)∑n=1∞(−1)ncos(n)