Which recurrence corresponds to an=3⋅2na_n = 3 \cdot 2^nan=3⋅2n?
an=2an−1a_n = 2a_{n-1}an=2an−1
an=3an−1a_n = 3a_{n-1}an=3an−1
an=an−1+2a_n = a_{n-1} + 2an=an−1+2
an=an−1+6a_n = a_{n-1} + 6an=an−1+6