Which property is always true about lcm(a,b)\text{lcm}(a, b)lcm(a,b)?
a∣lcm(a,b)a \mid \text{lcm}(a, b)a∣lcm(a,b) and b∣lcm(a,b)b \mid \text{lcm}(a, b)b∣lcm(a,b)
lcm(a,b)∣a\text{lcm}(a, b) \mid alcm(a,b)∣a and lcm(a,b)∣b\text{lcm}(a, b) \mid blcm(a,b)∣b
lcm(a,b)=a+b\text{lcm}(a, b) = a + blcm(a,b)=a+b
lcm(a,b)=a⋅b\text{lcm}(a, b) = a \cdot blcm(a,b)=a⋅b always