Which polynomial has roots that are the squares of the roots of x3−x2+1=0x^3 - x^2 + 1 = 0x3−x2+1=0?
x3−x2+2x−1=0x^3 - x^2 + 2x - 1 = 0x3−x2+2x−1=0
x3+x2+2x−1=0x^3 + x^2 + 2x - 1 = 0x3+x2+2x−1=0
x3−2x2+x−1=0x^3 - 2x^2 + x - 1 = 0x3−2x2+x−1=0
x3−x2−2x−1=0x^3 - x^2 - 2x - 1 = 0x3−x2−2x−1=0