Which point remains fixed under the transformation T(x,y)=(x+2,y−3)T(x, y) = (x+2, y-3)T(x,y)=(x+2,y−3)?
No points
(2,−3)(2, -3)(2,−3)
(0,0)(0, 0)(0,0)
(1,1)(1, 1)(1,1)