Which of these is equivalent to x2+1≡0(mod5)x^2 + 1 \equiv 0 \pmod{5}x2+1≡0(mod5)?
x≡1(mod5)x \equiv 1 \pmod{5}x≡1(mod5)
x≡2(mod5)x \equiv 2 \pmod{5}x≡2(mod5)
x≡3(mod5)x \equiv 3 \pmod{5}x≡3(mod5)
x≡4(mod5)x \equiv 4 \pmod{5}x≡4(mod5)