Which of these is a solution to x2−3y2=−2x^2 - 3y^2 = -2x2−3y2=−2?
(1,1)(1, 1)(1,1)
(5,3)(5, 3)(5,3)
(19,11)(19, 11)(19,11)
(2,2)(2, 2)(2,2)