Which of these is a solution to an=2an−1+1a_n = 2a_{n-1} + 1an=2an−1+1?
an=c2n−1a_n = c 2^n - 1an=c2n−1
an=c2n+1a_n = c 2^n + 1an=c2n+1
an=c2na_n = c 2^nan=c2n
an=c+2na_n = c + 2^nan=c+2n