Which of these are solutions to x+y+z=3x + y + z = 3x+y+z=3 with x,y,z≥1x, y, z \ge 1x,y,z≥1?
(1,1,1)(1, 1, 1)(1,1,1)
(2,1,0)(2, 1, 0)(2,1,0)
(1,2,0)(1, 2, 0)(1,2,0)
(3,0,0)(3, 0, 0)(3,0,0)