Which of the following values of xxx are solutions to the equation 22x+1−5⋅2x+2=02^{2x+1} - 5 \cdot 2^x + 2 = 022x+1−5⋅2x+2=0?
x=0x = 0x=0
x=1x = 1x=1
x=−1x = -1x=−1
x=2x = 2x=2