Which of the following matrices is the inverse of A=(cosθsinθ−sinθcosθ)A = \begin{pmatrix} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{pmatrix}A=(cosθ−sinθsinθcosθ)?
(cosθ−sinθsinθcosθ)\begin{pmatrix} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{pmatrix}(cosθsinθ−sinθcosθ)
(cosθsinθ−sinθcosθ)\begin{pmatrix} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{pmatrix}(cosθ−sinθsinθcosθ)
(−cosθsinθ−sinθ−cosθ)\begin{pmatrix} -\cos \theta & \sin \theta \\ -\sin \theta & -\cos \theta \end{pmatrix}(−cosθ−sinθsinθ−cosθ)
(1001)\begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}(1001)