Which of the following logical equivalences demonstrates the Absorption Law?
P∨(P∧Q)≡PP \lor (P \land Q) \equiv PP∨(P∧Q)≡P
P∧(P∨Q)≡PP \land (P \lor Q) \equiv PP∧(P∨Q)≡P
P∨(Q∧R)≡(P∨Q)∧(P∨R)P \lor (Q \land R) \equiv (P \lor Q) \land (P \lor R)P∨(Q∧R)≡(P∨Q)∧(P∨R)
Both a and b