Which of the following linear congruences have at least one solution?
3x≡2(mod6)3x \equiv 2 \pmod{6}3x≡2(mod6)
4x≡8(mod10)4x \equiv 8 \pmod{10}4x≡8(mod10)
6x≡3(mod12)6x \equiv 3 \pmod{12}6x≡3(mod12)
5x≡1(mod8)5x \equiv 1 \pmod{8}5x≡1(mod8)