Which of the following is true if λ\lambdaλ is an eigenvalue of AAA?
det(A−λI)=0\det(A - \lambda I) = 0det(A−λI)=0
det(A−λI)=1\det(A - \lambda I) = 1det(A−λI)=1
A−λI=0A - \lambda I = 0A−λI=0
AAA is invertible