Which of the following is equivalent to ∫1x2+2x+5dx\int \frac{1}{x^2+2x+5} dx∫x2+2x+51dx?
12tan−1(x+12)+C\frac{1}{2} \tan^{-1}(\frac{x+1}{2}) + C21tan−1(2x+1)+C
tan−1(x+1)+C\tan^{-1}(x+1) + Ctan−1(x+1)+C
14tan−1(x+12)+C\frac{1}{4} \tan^{-1}(\frac{x+1}{2}) + C41tan−1(2x+1)+C
12ln∣x2+2x+5∣+C\frac{1}{2} \ln|x^2+2x+5| + C21ln∣x2+2x+5∣+C