Which of the following is a solution to y′=y2y' = y^2y′=y2?
y=1C−xy = \frac{1}{C-x}y=C−x1
y=1x−Cy = \frac{1}{x-C}y=x−C1
y=ex2y = e^{x^2}y=ex2
y=x2+Cy = x^2 + Cy=x2+C