Which of the following functions y(x)y(x)y(x) is the solution to y′=2xyy' = 2xyy′=2xy with y(0)=3y(0) = 3y(0)=3?
y=3ex2y = 3e^{x^2}y=3ex2
y=ex2+2y = e^{x^2} + 2y=ex2+2
y=3e2xy = 3e^{2x}y=3e2x
y=x2+3y = x^2 + 3y=x2+3