Which interval of xxx satisfies the inequality sin2(x)−sin(x)<0\sin^2(x) - \sin(x) < 0sin2(x)−sin(x)<0 for x∈[0,2π]x \in [0, 2\pi]x∈[0,2π]?
(0, \pi)
(\pi/2, 3\pi/2)
(0, \pi/2) \cup (\pi/2, \pi)
(\pi, 2\pi)