Which integral represents the arc length of f(x)=ln(x)f(x) = \ln(x)f(x)=ln(x) for 1≤x≤e1 \le x \le e1≤x≤e?
∫1e1+ln2(x)dx\int_1^e \sqrt{1 + \ln^2(x)} dx∫1e1+ln2(x)dx
∫1e1+1x2dx\int_1^e \sqrt{1 + \frac{1}{x^2}} dx∫1e1+x21dx
∫1e(1+1x2)dx\int_1^e (1 + \frac{1}{x^2}) dx∫1e(1+x21)dx
∫1e1+1xdx\int_1^e \sqrt{1 + \frac{1}{x}} dx∫1e1+x1dx