Which integral is equivalent to ∫xx+1dx\int x \sqrt{x+1} dx∫xx+1dx using substitution u=x+1u=x+1u=x+1?
∫(u3/2+u1/2)du\int (u^{3/2} + u^{1/2}) du∫(u3/2+u1/2)du
∫(u3/2−u1/2)du\int (u^{3/2} - u^{1/2}) du∫(u3/2−u1/2)du
∫u1/2du\int u^{1/2} du∫u1/2du
∫(u2−u)du\int (u^2 - u) du∫(u2−u)du