Which identity is equivalent to 2sin2(θ)2\sin^2(\theta)2sin2(θ)?
1−cos(2θ)1 - \cos(2\theta)1−cos(2θ)
1+cos(2θ)1 + \cos(2\theta)1+cos(2θ)
cos(2θ)−1\cos(2\theta) - 1cos(2θ)−1
sin(2θ)\sin(2\theta)sin(2θ)