Which hyperbola has the same asymptotes as x24−y29=1\frac{x^2}{4} - \frac{y^2}{9} = 14x2−9y2=1?
x24−y29=5\frac{x^2}{4} - \frac{y^2}{9} = 54x2−9y2=5
x29−y24=1\frac{x^2}{9} - \frac{y^2}{4} = 19x2−4y2=1
x216−y236=1\frac{x^2}{16} - \frac{y^2}{36} = 116x2−36y2=1
All of the above