Which expression represents the general solution for dydx=1x\frac{dy}{dx} = \frac{1}{x}dxdy=x1?
y=ln∣x∣+Cy = \ln|x| + Cy=ln∣x∣+C
y=x+Cy = x + Cy=x+C
y=−1x2+Cy = -\frac{1}{x^2} + Cy=−x21+C
y=ex+Cy = e^x + Cy=ex+C