Which expression represents the Bezout identity for 121212 and 181818?
12(2)+18(−1)=612(2) + 18(-1) = 612(2)+18(−1)=6
12(−1)+18(1)=612(-1) + 18(1) = 612(−1)+18(1)=6
12(3)+18(−2)=012(3) + 18(-2) = 012(3)+18(−2)=0
12(0)+18(1)=1812(0) + 18(1) = 1812(0)+18(1)=18