Which expression represents the average value of f(t)=8tf(t) = 8tf(t)=8t on [0,2][0, 2][0,2]?
12−0∫028tdt\frac{1}{2-0} \int_0^2 8t dt2−01∫028tdt
∫028tdt\int_0^2 8t dt∫028tdt
18∫02tdt\frac{1}{8} \int_0^2 t dt81∫02tdt
2∫028tdt2 \int_0^2 8t dt2∫028tdt