Which expression represents sin(2θ)\sin(2\theta)sin(2θ)?
2sinθcosθ2\sin\theta\cos\theta2sinθcosθ
cos2θ−sin2θ\cos^2\theta - \sin^2\thetacos2θ−sin2θ
1−2sin2θ1 - 2\sin^2\theta1−2sin2θ
sin2θ+cos2θ\sin^2\theta + \cos^2\thetasin2θ+cos2θ