Which expression is the general solution for an=−an−1a_n = -a_{n-1}an=−an−1?
an=c(−1)na_n = c(-1)^nan=c(−1)n
an=c(1)na_n = c(1)^nan=c(1)n
an=c(−n)a_n = c(-n)an=c(−n)
an=c+(−1)na_n = c + (-1)^nan=c+(−1)n