Which expression is equivalent to 1−cos(2θ)1+cos(2θ)\frac{1-\cos(2\theta)}{1+\cos(2\theta)}1+cos(2θ)1−cos(2θ) using double angle identities?
tan2(θ)\tan^2(\theta)tan2(θ)
cot2(θ)\cot^2(\theta)cot2(θ)
sin2(θ)\sin^2(\theta)sin2(θ)
cos2(θ)\cos^2(\theta)cos2(θ)