Which expression is equivalent to Ac∪BcA^c \cup B^cAc∪Bc?
(A∪B)c(A \cup B)^c(A∪B)c
(A∩B)c(A \cap B)^c(A∩B)c
Ac∩BcA^c \cap B^cAc∩Bc
A∪BA \cup BA∪B