Which expression is equal to cos(2θ)1+sin(2θ)\frac{\cos(2\theta)}{1 + \sin(2\theta)}1+sin(2θ)cos(2θ)?
1−tanθ1+tanθ\frac{1 - \tan \theta}{1 + \tan \theta}1+tanθ1−tanθ
tan(θ)+1\tan(\theta) + 1tan(θ)+1
cot(θ)−1\cot(\theta) - 1cot(θ)−1
1+tanθ1−tanθ\frac{1 + \tan \theta}{1 - \tan \theta}1−tanθ1+tanθ