Which condition on zzz ensures that Re(z2)=0\text{Re}(z^2) = 0Re(z2)=0?
∣z∣=0|z| = 0∣z∣=0
zzz is purely real
zzz is purely imaginary or z=k(1±i)z = k(1 \pm i)z=k(1±i)
zzz is 1