Which condition is sufficient for two events AAA and BBB to be independent?
P(A∩B)=0P(A \cap B) = 0P(A∩B)=0
P(A∣B)=P(A)P(A|B) = P(A)P(A∣B)=P(A)
P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)
P(A∣B)+P(A∣Bc)=1P(A|B) + P(A|B^c) = 1P(A∣B)+P(A∣Bc)=1