Which condition is equivalent to saying P(A∣B)=P(A)P(A|B) = P(A)P(A∣B)=P(A)?
P(A∩B)=P(A)P(B)P(A \cap B) = P(A)P(B)P(A∩B)=P(A)P(B)
P(A∪B)=P(A)+P(B)P(A \cup B) = P(A) + P(B)P(A∪B)=P(A)+P(B)
P(A∣B)+P(Ac∣B)=0P(A|B) + P(A^c|B) = 0P(A∣B)+P(Ac∣B)=0
AAA is a subset of BBB