Which closed form satisfies the recurrence an=4an−1−3an−2a_n = 4a_{n-1} - 3a_{n-2}an=4an−1−3an−2?
an=2⋅3n+na_n = 2 \cdot 3^n + nan=2⋅3n+n
an=3⋅3n+2⋅1na_n = 3 \cdot 3^n + 2 \cdot 1^nan=3⋅3n+2⋅1n
an=5⋅2n−3⋅1na_n = 5 \cdot 2^n - 3 \cdot 1^nan=5⋅2n−3⋅1n
an=3n+2na_n = 3^n + 2^nan=3n+2n