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When using PPS (Probability Proportional to Size) sampling with replacement, the inclusion probability πi\pi_i for a unit ii selected in nn draws is given by πi=1(1pi)n\pi_i = 1 - (1 - p_i)^n, where pi=MiMjp_i = \frac{M_i}{\sum M_j}. If a unit has pi=0.02p_i = 0.02 and we take n=10n = 10 draws, what is the probability?