What is the general solution to y′=−3yy' = -3yy′=−3y?
y=Ce−3xy = C e^{-3x}y=Ce−3x
y=e−3x+Cy = e^{-3x} + Cy=e−3x+C
y=−3x+Cy = -3x + Cy=−3x+C
y=1/x3y = 1/x^3y=1/x3