What is the general solution to y′′+2y′=0y'' + 2y' = 0y′′+2y′=0?
y=C1+C2e−2xy = C_1 + C_2 e^{-2x}y=C1+C2e−2x
y=C1ex+C2e−2xy = C_1 e^x + C_2 e^{-2x}y=C1ex+C2e−2x
y=C1cos2x+C2sin2xy = C_1 \cos 2x + C_2 \sin 2xy=C1cos2x+C2sin2x
None