What is the derivative of f(x)=exlnxf(x) = \frac{e^x}{\ln x}f(x)=lnxex?
exlnx−ex/x(lnx)2\frac{e^x\ln x - e^x/x}{(\ln x)^2}(lnx)2exlnx−ex/x
ex/(1/x)e^x / (1/x)ex/(1/x)
ex(xlnx−1)x(lnx)2\frac{e^x(x\ln x - 1)}{x(\ln x)^2}x(lnx)2ex(xlnx−1)
Both a and c