What is the value of ∑n=1∞(12n−1−14n−1)\displaystyle \sum_{n=1}^{\infty} \left(\frac{1}{2^{n-1}} - \frac{1}{4^{n-1}}\right)n=1∑∞(2n−11−4n−11)?
111
23\frac{2}{3}32
43\frac{4}{3}34
222