What is the solution to y′=2xy' = 2xy′=2x with y(1)=2y(1) = 2y(1)=2?
y=x2y = x^2y=x2
y=x2+1y = x^2 + 1y=x2+1
y=2xy = 2xy=2x
y=x2+2y = x^2 + 2y=x2+2