What is the slope of the normal line to the ellipse x216+y24=1\frac{x^2}{16} + \frac{y^2}{4} = 116x2+4y2=1 at the point (2,3)(2, \sqrt{3})(2,3)?
2/32/\sqrt{3}2/3
−2/3-2/\sqrt{3}−2/3
3/2\sqrt{3}/23/2
−3/2-\sqrt{3}/2−3/2