What is the result of the Limit Comparison Test for ∑n=1∞2n2+5n4−2n+1\sum_{n=1}^{\infty} \frac{2n^2 + 5}{n^4 - 2n + 1}∑n=1∞n4−2n+12n2+5 with bn=1n2b_n = \frac{1}{n^2}bn=n21?
L=0L = 0L=0
L=1L = 1L=1
L=2L = 2L=2
L=∞L = \inftyL=∞