What is the result of the Integral Test application on ∑n=1∞1n2+1\sum_{n=1}^{\infty} \frac{1}{n^2+1}∑n=1∞n2+11?
Converges because ∫1∞1x2+1dx\int_1^{\infty} \frac{1}{x^2+1} dx∫1∞x2+11dx is finite
Diverges because ∫1∞1x2+1dx\int_1^{\infty} \frac{1}{x^2+1} dx∫1∞x2+11dx is infinite
Converges because ∫1∞1x2+1dx=π\int_1^{\infty} \frac{1}{x^2+1} dx = \pi∫1∞x2+11dx=π
The test is inconclusive