What is the result of solving the initial value problem dydx=2x\frac{dy}{dx} = 2xdxdy=2x with y(0)=4y(0) = 4y(0)=4?
y=x2y = x^2y=x2
y=x2+4y = x^2 + 4y=x2+4
y=2x2+4y = 2x^2 + 4y=2x2+4
y=x2+4xy = x^2 + 4xy=x2+4x